Acids including formic acidic and you may acetic acid is partially ionised inside the services and have low K

Obtain the worth of solubility tool out of molar solubility

2. Acids such as HCI, HNO₃ are almost completely? onised and hence they have high K_a value i.e., K_a for HCI at 25°C is 2 x 10 6 .

cuatro. Acids with K_a value greater than ten are considered as strong acids and less than one considered as weak acids.

1. HClO₄, HCI, H₂SO₄ – are strong acids
2. NH₂ – , O 2- , H – – are strong bases
3. HNO₂, HF, CH₃COOH are weak acids

Question 5. pH of a neutral solution is equal to 7. Prove it. in neutral solutions, the concentration of [H₃O + ] as well as [OH – ] are equal to 1 x 10 -7 M at 25°C.

2. The pH of a neutral solution can be calculated by substituting this [H₃O + ] concentration in the expression pH = – log₁₀ [H₃O + ] = – log₁₀ [1 x 10 -7 ] = – ( – 7)log \(\frac < 1>< 2>\) = + 7 (l) = 7

Answer: 1

Question 7. https://datingranking.net/escort-directory/honolulu/ When the dilution increases by 100 times, the dissociation increases by 10 times. Justify this statement. Answer: (i). Let us consideran acid with K_a value 4 x 10 4 . We are calculating the degree of dissociation of that acid at two different concentration 1 x 10 -2 M and 1 x 10 -4 M using Ostwalds dilution law

(iv) i.e., in the event the dilution develops by the 100 minutes (focus decreases from just one x 10 -2 M to 1 x 10 -cuatro Yards), the brand new dissociation grows because of the ten minutes.

1. Shield are a solution using its a variety of poor acid and its particular conjugate foot (or) a failing ft and its particular conjugate acid.
2. This barrier service resists radical alterations in their pH upon introduction away from a tiny levels of acids (or) basics and therefore ability is named shield step.
3. Acidic buffer solution, Solution containing acetic acid and sodium acetate. Basic buffer solution, Solution containing NH₄O and NH₄Cl.

1. The new buffering function away from an answer are going to be measured with regards to regarding shield capability.
2. Buffer index ?, once the a decimal way of measuring the fresh new boundary capabilities.
3. It’s recognized as what number of gram competitors regarding acidic otherwise base put in 1 litre of one’s shield substitute for change their pH because of the unity.
4. ? = \(\frac < dB>< d(pH)>\). dB = number of gram equivalents of acid / base added to one litre of buffer solution. d(pH) = The change in the pH after the addition of acid / base.

Matter 10. Exactly how is actually solubility device is accustomed determine the new rain away from ions? When the tool away from molar intensity of this new component ions i.e., ionic tool is higher than the brand new solubility tool then substance becomes precipitated.

2. When the ionic Product > K_sp precipitation will occur and the solution is super saturated. ionic Product < K_sp no precipitation and the solution is unsaturated. ionic Product = K_sp equilibrium exist and the solution ?s saturated.

step 3. By this means, the fresh new solubility product finds good for determine if an ionic material becomes precipitated when services that contain the constituent ions was blended.

Concern eleven. Solubility will likely be calculated away from molar solubility.we.age., the most level of moles of one’s solute which may be mixed in a single litre of your own solution.

3. From the above stoichiometrically balanced equation, it is clear that I mole of X_m Y_n(s) dissociated to furnish ‘m’ moles of x and ‘n’ moles of Y. If’s’ is the molar solubility of X_m Y_nthen Answer: [X n+ ] = ms and [Y m- ] = ns K_sp = [X n+ ] m [Y m- ] n K_sp = (ms) m (ns) n K_sp = (m) m (n) n (s) m+n